Description
The addition/subtraction formula "X [operator] Y = Z" is given as a parameter. If the formula is correct, complete the solution function to return the array containing "X" in order if "O" is incorrect.
Restrictions
- There is always one space between the arithmetic symbol and the number. However, there is no space between the minus sign and the number that displays the negative number.
- 1 ≤ quiz's length ≤ 10
- X, Y, and Z are integers consisting of numbers from 0 to 9, respectively, and each number may have one minus sign at the front, which means a negative number.
- X, Y, and Z do not start with zero.
- -10,000 ≤ X, Y ≤ 10,000
- -20,000 ≤ Z ≤ 20,000
- "Operator" is either + or -.
Quiz | Result |
["3 - 4 = -3", "5 + 6 = 11"] | ["X", "O"] |
["19 - 6 = 13", "5 + 66 = 71", "5 - 15 = 63", "3 - 1 = 2"] | ["O", "O", "X", "O"] |
Input/Output Example Description
Input/Output Example #1
3 - 4 = -3 is the wrong formula, so "X", and 5 + 6 = 11 is the correct formula, so "O", so return [X], "O".
Input/Output Example #2
19 - 6 = 13 is the correct formula, so "O", 5 + 66 = 71 is the correct formula, 5 - 15 = 63 is the wrong formula, and 3 - 1 = 2 is the correct formula, so return ["O", 'O'].
def solution(quiz):
answer = []
for q in quiz:
spl_q = q.split()
if spl_q[1] == '-':
if int(spl_q[0]) - int(spl_q[2]) == int(spl_q[4]):
answer.append("O")
else:
answer.append("X")
if spl_q[1] == '+':
if int(spl_q[0]) + int(spl_q[2]) == int(spl_q[4]):
answer.append("O")
else:
answer.append("X")
return answer
Discussion
The key point of this probelm is to use split method and using elements to decide whether the equation is correct or incorrect throughly.
I forgot how to use split method in Python because I didn't revise it.
When calculating numbers that are in string type, I need to convert all the string element into integers, and I missed this basic method.
I should solve more problems related with spliting elements in lists.
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